Using trigonometry and the sine rule the area of the regular 5 sided pentagon with a perimeter of 50cm works out as 172.048 square cm rounded to 3 decimal places.
A pentagon is a 2-D shape. You can't find the volume of it unless it's 3-D. The formula for the area of a pentagon has something to do with the perimeter, the number of sides, the apothem, and the number 2.
Area of a regular pentagon with a known side S can be closely approximated by formula 5S2/4 tan 36. Taking 4 tan 36 as 2.906 then the area sought is 2000/2.906 ie 688.23 sq units.
The area of a pentagon of side length t is given by the formula t2 (sqrt 25 + 10 (sqrt 5)) / 4, or 5t2 tan (54o) / 4. In this case, a pentagon with one side of 10cm has an area of 102 (sqrt 25 + 10 (sqrt 5)) / 4 = 172.05 cm2 (accurate to two decimal places).
27.50
An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.
The formula is 1/2 (apothem) (perimeter)
Area 42 cm2, perimeter 26 cm.
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
The area ( A ) of a regular pentagon can be calculated using the formula ( A = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem} ). For a regular pentagon with an apothem of 4, we first need the perimeter. The perimeter ( P ) can be found using the formula ( P = 5s ), where ( s ) is the length of one side. However, without knowing the side length, we can use the relationship between the apothem and side length in a regular pentagon, leading to the area being ( A = \frac{5 \times s \times 4}{2} ). Assuming ( s ) as 4 (for simplicity), the area would be ( A = 40 ).
The perimeter of the pentagon would be 18 x 5 = 90 centimetres. The area of the pentagon, rounded to two decimal places, would be (5 x 182 x tan(54))/4 = 272.89 cm2.
The area ( A ) of a regular pentagon can be calculated using the formula ( A = \frac{1}{2} \times \text{perimeter} \times \text{apothem} ). The perimeter of the pentagon is ( 5 \times 9.4 = 47 ) feet. Thus, the area is ( A = \frac{1}{2} \times 47 \times 6.5 = 152.75 ) square feet.
The boy had to find the area and perimeter of the pentagon.
Area = 139.36 ft2
The area of a regular pentagon can be calculated using the formula: ( \text{Area} = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem} ). For a pentagon with a side length of 9 mm, the perimeter is ( 5 \times 9 = 45 ) mm. Using the apothem length of 6.2 mm, the area is ( \frac{1}{2} \times 45 \times 6.2 = 139.5 ) square millimeters. Thus, the area of the pentagon is 139.5 mm².
add all of the triangle area in a pentagon to get areaThe area A of a regular polygon with n sides each s units long, perimeter p, and apothem a:A = (ans)/2 or A = (ap)/2.
About 387 m^2 1.72*s^2 s=perimeter/5 s=75/5=15 1.72*15*15=387
Area = 1,548.43 ft2