Use the formula for the area of a triangle, which is 0.5 x base x height. Since the 10' and the 15' are at right angles, you can take any of them to be the "base", in which case the other one is the "height".
432180. The legs are 441 and 1960.
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
They are the "legs" of the triangle.
Lets work it out:- If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
The length of the hypotenuse of a right triangle whose legs measure 45 cm and 60 cm is: 75 cmThe area of the triangle is 1,350 cm2
432180. The legs are 441 and 1960.
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
5cm
The area of a right triangle is 1/2 of the product of the two legs.
50
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
Draw a right angled triangle with legs of 4cm and 6cm
Area of the triangle: 0.5*6*5 = 15 square units
175cm2