Lets work it out:-
If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
The area of triangle is : 35.0
Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
A triangle cannot have four lengths!
First convert the base to the same kind of units you have defined the area in (but linear); 24 inches. The area of a triangle is half of the base times the height .12 (half the base) times what is 144?12, the height (altitude) of the triangle is 12 inches (one foot).
If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case. The area of a right-angled triangle is given by: A = base x height / 2 = 5 inches x 6 inches / 2 = 15 square inches Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by: A = 4 x 15 square inches = 60 square inches
Area = 0.5*21*28 = 294 square inches
294 in^2
270 in2
It is: 0.5*25*20 = 250 square inches It doesn't matter whether or not a triangle is a right triangle; the area is always half of the base times the height.
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
The area is 294 square inches.
Area = 0.5*21*28 = 294 square inches
A "3-4-5" right angled triangle has an area of 6 sq inches. (3x4)/2
The area is 272 square inches.32*17/2=272
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
18 square inches
Area = 0.5*6*12 = 36 square inches