answersLogoWhite

0


Best Answer

This is obviously a square that cannot exist in our universe, where all sides of a square ere equal....

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the area of a square with the sides of 30m and 15m?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Algebra

A path 1m wide is built along the border and inside a square garden of side 30cmfind the area of the path?

Let ABCD be the border of square garden of side 30m and the shaded region be the path Then AD = 30m , XP=1m, SY = 1m and XY = AD ⇒ XP + PS + SY = AD ⇒ PS = AD - XP - SY = 30m - 1m - 1m = 28m ∴ PQRS in a square of side 28m ∴ The area of path = Area of ABCD - Area of PQRS


Factor 4m to the 6th -30m to the 5 36m to the 4th?

2m4(m2-15m+18) i hope this is right! srry if its not i just did it for hw


What is the area of a circle with a diameter of 30m?

The formula for area of a circle is Pi x r (squared), A = Pi(rxr). So since the diameter is 30 you divide it by two and get 15 and then square it and multiply it by pi and get 706.86 meters.


What is the height of a solid with a volume of 120m cubed and a base area of 30m squared?

4m because V=BxHso H =120/30=4


A 1.5m wide footpath runs all along the fence outside a park 40m long and 30m wide What is the perimeter of the fence and what is the area of the footpath?

As two dimensions of the park are given, it can be assumed to be a rectangle in shape. → perimeter of fence = 40m + 30m + 40m + 30m = 140m For the area of the path, it runs along all the perimeter of the fence so its length is 140m and its width is 1.5m → the area of the footpath next to the fence is 140m x 1.5m = 210 m2. However, this area only includes the footpath that has one side next to the fence but excludes those parts of the footpath that go round the corners of the fence. As the path is given as 1.5m wide, it could be assumed that the path at each of the corners will be a quarter circle of radius 1.5m. As there are four of these quarter circles, their total area is the area of a whole circle: → area of the path = 210m2 + π x (1.5m)2 = 140m2 + 2.25π m2 ≈ 217.07 m2 The corners could also be squared off, so that each is a square of side 1.5m: → area of the path = 210m2 + 4 x (1.5m)2 = 219 m2.

Related questions

What is the area of a 15m and 30m square?

15m and 30 m


Which is the GCF of 12m 15m and 30m?

The GCF of 12m, 15m and 30m is 3m.


What are the dimensions of rectangular lot if the perimeter is 90m and the area is 450m2?

The dimensions of the rectangular lot are: 30m by 15m


What is the gcf of 12m 15m and 30m?

The GCF is: 3m


15m plus 3 over 2 equals -6?

15m+3/2 = -6 30m+3 = -12 30m = -15 m = -1/2


What the perimeter of a square with 7.5m sides?

4*7.5 = 30m


How far can a ww1 pistol shoot?

30m-50m double action 15m-25m reapeter


Mary wants to build a fence around her rectangular garden Its 10m wide and 15m longHow much fencing does she need to buy?

As the rectangular garden is 10m wide, then two sides will require 10m of fencing. Thus 2*10 = 20m of fencing. It is also 15m long, so two sides will require 15m of fencing. Thus 2*15 = 30m of fencing. Adding up all 4 sides => 20+30 = 50m of fencing.


What is the perimeter of a square with side lengths of 7.5 meters?

30 meters (7.5m x 4 sides = 30m)


Best time frame for day trading?

Day traders will usually use 1m, 5m, 15m or 30m time frames. Which time frame to choose is depends on the trader's character, an aggressive trader will probably use the 1m and 5m, a more serene trader will probably use the 15m or 30m.


What is the area of a rectangle with 30m length and 1m width?

30*1 = 30 square metres.


A path 1m wide is built along the border and inside a square garden of side 30cmfind the area of the path?

Let ABCD be the border of square garden of side 30m and the shaded region be the path Then AD = 30m , XP=1m, SY = 1m and XY = AD ⇒ XP + PS + SY = AD ⇒ PS = AD - XP - SY = 30m - 1m - 1m = 28m ∴ PQRS in a square of side 28m ∴ The area of path = Area of ABCD - Area of PQRS