4/5
opposite/hypotenuse = sin(x) adjacent/hypotenuse = cos(x) opposite/adjacent = tan(x) where 'x' is the angle in question.
The six main trigonometric functions are sin(x)=opposite/hypotenuse cos(x)=adjacent/hypotenuse tan(x)=opposite/adjacent csc(x)=hypotenuse/opposite cot(x)=adjacent/opposite sec(x)=hypotenuse/adjacent Where hypotenuse, opposite, and adjacent correspond to the three sides of a right triangle and x corresponds to an angle in that right triangle.
There are three sides, hypotenuse, opposite and adjacent. But the adjacent and opposite are not fixed sides: it depends on which of the two acute angles you are examining.For either of the non-right angles, the adjacent side is the one which forms the angle, along with the hypotenuse. For the given angle θ, the length of the adjacent side compared to the hypotenuse (adjacent/hypotenuse) is the cosine (cos θ).
Adjacent side / Hypotenuse
Yes. If you know two angles of a triangle, then you know all three. Why? Because they sum to 180 deg. So you have the hypotenuse and the angles at either end then you have ASA. AAS may not be sufficient for congruence but ASA IS. Another way of looking at it: suppose the hypotenuse is h and the known acute angle is x. Then, the side adjacent to the angle is h*cos(x) while the side opposite is h*sin(x). So the two hypotenuses are of length h, the two sides adjacent to the known acute angle are h*cos(x) each and the sides opposite are h*sin(x). And all three pairs of angles are equal. What else do you need to show congruence?
Opposite over hypotenuse. Sin=opposite/hypotenuse cos=adjacent/hypotenuse tan=opposite/adjacent
Sine(Sin) Cosine(Cos) Tangent(Tan) ---- -Sin of angle A=opposite leg of angle A / hypotenuse -Cos of angle A= Adjacent leg of angle A / Hypotenuse -Tan of angle A= opposite leg of angle A / Adjacent lef of angle A
Cos(angle) = adjacent / hypotenuse. Cos(a) = a/h Substitute Cos(X) = 5/13 = 0.384615... A = Cos^*-1( 0.384615 .... A = 67.38013505... degrees.
The side adjacent to theta divided by the hypotenuse, or the angle opposite of the right angle
**Sin**e(angle) = opposite / hupotenuse NB **Cos**ine(angle) = adjacent / hypotenuse **Tan**gent(angle) = opposite/adjacent.
Sine is opposite side of angle over hypotenuse. Cosine is adjacent side of angle over hypotenuse. Tangent is the opposite side over the adjacent side.
Yes. You will need to use trigonometry. sin (angle) = opposite/hypotenuse cos (angle) = adjacent/hypotenuse tan (angle) = opposite/adjacent
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
It is: cos^-1(12/13) = 22.61986495 degrees
you need a calculator to do Sin-1 Opposite/hypotenuse OR Cos-1 Adjacent/Hypotenuse OR Tan-1 Opposite/Adjacent
opposite/hypotenuse = sin(x) adjacent/hypotenuse = cos(x) opposite/adjacent = tan(x) where 'x' is the angle in question.
The six main trigonometric functions are sin(x)=opposite/hypotenuse cos(x)=adjacent/hypotenuse tan(x)=opposite/adjacent csc(x)=hypotenuse/opposite cot(x)=adjacent/opposite sec(x)=hypotenuse/adjacent Where hypotenuse, opposite, and adjacent correspond to the three sides of a right triangle and x corresponds to an angle in that right triangle.