4in2
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two square inches
3*sqrt(3)/2*r^2
The cross section of a cylinder is a circle. diameter = radius x 2 area_circle = π x radius2 ⇒ radius = √(area_circle ÷ π) ⇒ diameter = √(area_circle ÷ π) x 2 = √(706.86 sq in ÷ π) x 2 ≈ 30 in
If we denote the measure of the length side of the circumscribed square with a, then the vertexes of the inscribed square will point at the midpoint of the side, a, of the circumscribed square.The area of the circumscribed square is a^2The square measure of the length of the inscribed square, which is also the area of this square, will be equal to [(a/2)^2 + (a/2)^2]. Let's find it:[(a/2)^2 + (a/2)^2]= (a^2/4 + a^2/4)= 2(a^2)/4= a^2/2Thus their ratio is:a^2/(a^2/2)=[(a^2)(2)]/a^2 Simplify;= 2
The area of a square is the (perimeter/4)^2. The perimeter is 52, so 52/4=13. 13^2 is 169. The area of the square is 169 cm.^2.