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What is the cubic polynomial in standard form with roots 3 -6 and 0?
Acrownamedallen
A cubic with roots a, b, c has form:
f(x) = (x - a)(x - b)(x - c)
Thus the cubic with roots 3, -6 and 0 is given by:
f(x) = (x - 3)(x - -6)(x - 0)
→ f(x) = (x - 3)(x + 6)x
→ f(x) = (x² + 3x - 18)x
→ f(x) = x³ + 3x² - 18x
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∙ 7y ago
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