hyperbola
find the constant difference for a hyperbola with foci f1 (5,0) and f2(5,0) and the point on the hyperbola (1,0).
A hyperbola is another form of a conical section graph like a parabola or ellipse. Its general form is x^2/a - y^2/b = 1.
there is only one way i know how to find the slope of a hyperbola and that is taking the implicit derivative of its equation, and solving for dy/dx but the answer is Slope= (x)*(b^2) / (y)*(a^2)
(y-6)^2/8^2-(x+5)^2/2^2=1
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hyperbola
hyperbola
denominators
denominators
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
If the equation of a hyperbola is ( x² / a² ) - ( y² / b² ) = 1, then the joint of equation of its Asymptotes is ( x² / a² ) - ( y² / b² ) = 0. Note that these two equations differ only in the constant term. ____________________________________________ Happy To Help ! ____________________________________________
ellipse are added hyperbola are subtracted
7/12 and 7/12 is the answer
Unitary Elactic
find the constant difference for a hyperbola with foci f1 (5,0) and f2(5,0) and the point on the hyperbola (1,0).
we know from total expenditure method of measuring elasticity of demand that if total expenditure remains the same when price changes, elasticity is unitary. rectangular hyperbola is a curve under which all rectangular areas are equal. also, each rectangular area shows total expenditure on the commodity. along the curve, even if price changes, total expenditure remains the same, so rectangular hyperbola shows the elasticity of 1.