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How is the length of a diagonal of a square found?
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
What is the diagonal of 11 square inches?
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
In square diagonal is equal to?
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
Find the diagonal of a square?
Diagonal = sqrt (twice the square of a side) eg: square of side 8 units, d = sqrt(2 x 64) = sqrt 128 = 11.3137
What is the side length of a square with a diagonal of 16?
Oh, what a happy little question! To find the side length of a square with a diagonal of 16, we can use the Pythagorean theorem. Since the diagonal, side length, and side length form a right triangle, we can use the formula a^2 + b^2 = c^2, where a and b are the side lengths and c is the diagonal. In this case, we have 2 sides of the square equal to each other, so we can simplify the equation to 2a^2 = 16^2. Solving this, we find that the side length of the square is 8.
