-6
Using the distance formula from (3, 1) to (7, 1) is 4 units
You can get distance and hours and directions from Mapquest.com
The distance between the points of (4, 3) and (0, 3) is 4 units
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
6
1
Using the distance formula from (3, 1) to (7, 1) is 4 units
You can get distance and hours and directions from Mapquest.com
58
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
15
7 1/2
To find the distance between the points (1, 4) and (-5, 7), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the coordinates, we get ( d = \sqrt{((-5) - 1)^2 + (7 - 4)^2} = \sqrt{(-6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} ). Therefore, the distance between the points is ( 3\sqrt{5} ) or approximately 6.71 units.
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
The distance between the points of (4, 3) and (0, 3) is 4 units
The distance between the points is two times the square root of 3.