0
-6
What else can I help you with?
What is the distance between the points named by (3 1) and (7 1) on the coordinate plane?
Using the distance formula from (3, 1) to (7, 1) is 4 units
Find the distance between (-4 2) and (-7 -6).?
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Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between the points (-7 -13) and (8 -5)?
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
What is the distance between the points 4 7 and 7 8?
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
Find the distance between the points with the given coordinates (7 -1) and (7 3).?
To find the distance between the points (7, -1) and (7, 3), we can use the distance formula. Since both points have the same x-coordinate, the distance is simply the difference in the y-coordinates: |3 - (-1)| = |3 + 1| = 4. Therefore, the distance between the two points is 4 units.
What distance between -1 -7?
6
What is the expression for the distance between -6 and -7?
1
What is the distance between the points named by (3 1) and (7 1) on the coordinate plane?
Using the distance formula from (3, 1) to (7, 1) is 4 units
Find the distance between (-4 2) and (-7 -6).?
You can get distance and hours and directions from Mapquest.com
What is the distance between -2 1 and 3 7?
58
What is the distance between the points named by -3 1 and -7 1 on the coordinate plane?
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
Find the distance between the points -5 -3 and 7 6?
15
Distance between the pair of points-1-4and-5-7?
To find the distance between the points (1, 4) and (-5, 7), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the coordinates, we get ( d = \sqrt{((-5) - 1)^2 + (7 - 4)^2} = \sqrt{(-6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} ). Therefore, the distance between the points is ( 3\sqrt{5} ) or approximately 6.71 units.
What is the distance between Sudbury and Dryden Ont?
7 1/2
Distance between 8 -13 and 1 -7 Midpoint between 8 -13 and 1 -7?
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
