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It is the values of x, for which g(x) is defined.
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Is x the numbers that are domains of both f and g in the function fgx?
No. The set of x-values are the domain for only g. This will result in a set of images, which will be g(x). This set of g(x) values are the domain of f.
What is the domain of g x equals the square root of x plus 1?
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
What is the domain of the function G of F of x when F of x equals 8 minus x G of y equals square root of y G of F of x equals square root of 8 minus x?
x
What is meant by f of g of x Specifically address the domain and range?
You would have been given a function for f(x) and another function for g(x). When you want to find f(g(x)), you put the function for g(x) wherever x occurs in f(x). Example: f(x)=3x+2 g(x)=x^2 f(g(x))=3(x^2)+2 I'm not sure what you mean by address domain and range. They depend on what functions you're given.
What happens when you add or subtract from the original function?
That all depends on the functions you are given for the problem! When you add or subtract from the original function, then we obtain the new function. If you combine the functions with different domains, then the domain of the addition/subtract obeys whatever domain other function has. For instance: f(x) = 1/x and g(x) = x f(x) + g(x) = (1/x) + x = (1 + x²)/x Then, the domain is all real values except 0 since x = 0 makes the denominator zero, hence making the whole expression undefined. If x = 0, then this makes f(0) undefined.
If f-1(x)g(x) inverse then the domain of g(x) the range of f(x)?
If f(x) is the inverse of g(x) then the domain of g(x) and the range of f(x) are the same.
What is domain of f plus g of x and f over g of x when f of x is square root 3 minus 2x and g of x is x over x-5?
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
If F(x) x plus 2 and G(y) what is the domain of G(F(x))?
It is necessary to know the domain of x and also what the function G(y) is before it is possible to answer the question.
Is x the numbers that are domains of both f and g in the function fgx?
No. The set of x-values are the domain for only g. This will result in a set of images, which will be g(x). This set of g(x) values are the domain of f.
What is the domain of g x equals the square root of x plus 1?
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
What is the domain of the function G of F of x when F of x equals 8 minus x G of y equals square root of y G of F of x equals square root of 8 minus x?
x
What is meant by f of g of x Specifically address the domain and range?
You would have been given a function for f(x) and another function for g(x). When you want to find f(g(x)), you put the function for g(x) wherever x occurs in f(x). Example: f(x)=3x+2 g(x)=x^2 f(g(x))=3(x^2)+2 I'm not sure what you mean by address domain and range. They depend on what functions you're given.
Fungsi konstan f(x)= 2 dan fungsi linier g(x) =x - 3. Tentukan domain dan range dari g(x)/f(x)?
-1
What is the domain of g of x is equal to negative 2 times x?
anything can be put into it so... (-infinity,infinity)
Determine the inverse g(x) of the function f(x) = (1+(4/x)), stating its domain and range. Verify that f(g(x)) = g(f(x))=x and that gā²(f(x)) = (1/(fā²(x))?
Let f(x) = y y = 1 + (4/x) Now replace y with x and x with y and find equation for y x = 1 + (4/y) (x-1) = (4/y) y = 4/(x-1) This g(x), the inverse of f(x) g(x)= 4/(x-1) The domain will be all real numbers except when (x-1)=0 or x=1 So Domain = (-ā,1),(1,+ā) And Range = (-ā,0),(0,+ā) f(g(x)) = f(4/(x-1)) = 1 + 4/(4/(x-1)) = 1+(x-1) = x g(f(x)) = g(1+(4/x)) = 4/((1+(4/x))-1) = 4/(4/x) = x So we get f(g(x)) = g(f(x)) Notice the error in copying the next part of your question It should be g'(f(x)) = 1/(f'(g(x))) g'(f(x)) = d/dx (g(f(x))) = d/dx (x) = 1 f'(g(x)) = d/dx (f(g(x))) = d/dx (x) = 1 1/[f'(g(x))] = 1/1 = 1 g'(f(x)) = 1/f'(g(x)) ( Notice the error in copying your question)
What is the domain of the composite function G F x?
All real numbers except 2
What is the range of g of x equals square root of x plus 3?
First of all, g(x) is not a proper function since, many x values can have two values for g(x). Furthermore, the answer will depend on what the domain is, but you have not bothered to share that crucial bit of information.
