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What else can I help you with?
How do you to sketch a graph of a function whose domain is in the closed interval 0-4 and whose range is the set of two numbers 2 and 3?
Find the domain of the relation then draw the graph.
Inverse function 2x plus 4?
y=2x+4 --> x=2y+4 ==> y=(x-4)/2
What is the domain range asymptote and intercept of the equation y equals 4 times 2 exponent x?
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
What is the inverse function of y -2 3x plus 2?
If you mean: y-2 = 3x+2 then as a straight line equation it is y = 3x+4
Is x equals the square root of y-4 a function?
The square root operation is not a function because for each value of y there can be 2 values of x - the principal square root and its negative. This can only be rectified by limiting the range of the opearation to the principal or positive square root. Furthermore, it also depends on the domain of the function. If y<4 then the square root is not defined within Real numbers. So, for y ≥ 4, x = +sqrt(y-4) is a function.
How do you find the range of the function with the given domain?
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
What is the range of the function f(x) -10x for the domain -4 -2 0 2 4?
To find the range of the function ( f(x) = -10x ) for the given domain (-4, -2, 0, 2, 4), we can evaluate the function at each point in the domain. For ( x = -4 ), ( f(-4) = 40 ) For ( x = -2 ), ( f(-2) = 20 ) For ( x = 0 ), ( f(0) = 0 ) For ( x = 2 ), ( f(2) = -20 ) For ( x = 4 ), ( f(4) = -40 ) Thus, the range of the function is ([-40, 40]).
What is the range of the function f(x) 4x plus 9 given the domain D -4 -2 0 2?
The range is {-7, 1, 9, 17}.
What is the range of f(x) -x2 plus 4 if the domain is 201?
The function ( f(x) = -x^2 + 4 ) is a downward-opening parabola. The vertex, which is the maximum point, occurs at ( x = 0 ) and gives the maximum value of ( f(0) = 4 ). As ( x ) moves away from 0 within the domain, the function decreases, reaching a minimum value at the edges of the domain. If the domain is limited to 201, the range of ( f(x) ) will be from ( -x^2 + 4 ) evaluated at the endpoints of that domain, specifically ( f(201) = -201^2 + 4 = -40400 + 4 = -40396 ). Therefore, the range of ( f(x) ) when the domain is 201 is ( [-40396, 4] ).
What is the domain of x plus 8 divided by x2-4?
The domain is all real numbers except when the denominator equals zero: x2 - 4 = 0 x2 = 4 x = 2, -2 So the domain is all real numbers except 2 and -2.
What is the range of the function fx 3.2x for the domain -4 -2 0 2 4?
It is -12.8, -6.4, 0, 6.4 and 12.8
Which is a zero function x2 plus 6x plus 8?
(x + 2)(x + 4) x = -2, -4
What is the example of the range and domain in a function?
A function is a mapping from one set to another. It may be many-to-one or one-to-one. The first of these sets is the domain and the second set is the range. Thus, for each value x in the domain, the function allocates the value f(x) which is a value in the range. For example, if the function is f(x) = x^2 and the domain is the integers in the interval [-2, 2], then the range is the set [0, 1, 4].
What is the value of x in 3(x-2)x plus 4?
x can have any value in the domain.
What is domain and mean of a set of numbers?
The mean is synonymous with the average, the sum of the numbers divided by the quantity of the numbers. For example, the average or mean of 2, 4 and 9 is 5, because (2 + 4 + 9) ÷ 3 = 5. I am not familiar with the term domain being a property of a set of constants. I understand a domain to be a property of a mathematical function; specifically, the domain of a function is the set of all possible inputs to the function that yield real individual outputs. For example, if a function of x is 4 ÷ (x - 2), the domain of x is any real number other than 2, since 2 would cause division by zero, so the output would not be a real number.
Is it ever possible for the domain and range to have different numbers of entries what happens when this is the case?
Yes. Typical example: y = x2. To avoid comparing infinite sets, restrict the function to integers between -3 and +3. Domain = -3, -2 , ... , 2 , 3. So |Domain| = 7 Range = 0, 1, 4, 9 so |Range| = 4 You have a function that is many-to-one. One consequence is that, without redefining its domain, the function cannot have an inverse.
How do you state the domain of this relation 5) (2 3) (1 -4) (-3 3) (-1 -2)?
If this is the whole of the function, then the domain is {2, 1, -3, -1}. That set can be put in increasing order if you wish but that is not necessary.
