Equation of circle: (x-3)^2 +(y+5)^2 = 13
It is (x - 3)2 + (y + 5)2 = 13.
In the case of a circle: Diameter: The distance through the circle - from one end to the other, passing through the center. Circumference: The distance around the circle.
The equation of the circle is: x^2 + y^2 = 81
yes a diameter passes through the center of a circle
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
Equation of circle: (x-2)^2 +(y+9)^2 = 49
a diameter
The line passing through the center of a circle with two endpoints on the circle is the circle's diameter.
This is the diameter of the circle.
That's a diameter of the circle.
It is (x + 2)^2 + (y - 1)^2 = 4
A line passing through the center and crossing the circle.
It is the diameter of the circle.
x2 + (y - b)2 = b2 or, equivalently, x2 + y2 - 2by = 0
No, a secant line does not pass through the center of a circle. A secant line is a line that intersects a circle in two distinct points. Only a line passing through the center of a circle is called a diameter.
Yes because the diameter of a circle is its largest chord passing through the center of the circle.
diameter
A diameter is the length of a chord passing through the center of a circle.