It is (x + 2)^2 + (y - 1)^2 = 4
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
Diameter.
A straight line passing from side to side going through the middle of a circle or sphere is a diameter.
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
a diameter
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
x2 + (y - b)2 = b2 or, equivalently, x2 + y2 - 2by = 0
The line passing through the center of a circle with two endpoints on the circle is the circle's diameter.
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
Equation of circle: (x-3)^2 +(y+5)^2 = 13
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
Perpendicular to a line passing through the center of the Earth.
A diameter.
Half of a sphere cut by a plane passing through its center.
A diameter is the length of a chord passing through the center of a circle.