Points: (2, -3) and (-2, 0)
Slope: -3/4
Equation: y = -0.75x-1.5
It is (x + 2)^2 + (y - 1)^2 = 4
It is (x + 2)^2 + (y + 3)^2 = 9
Diameter.
A straight line passing from side to side going through the middle of a circle or sphere is a diameter.
If you mean a center of (3, 10) passing through (12, 12) then the radius is the square root of 85 which is about 9.2195 rounded to four decimal places.
a diameter
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
It is (x + 2)^2 + (y - 1)^2 = 4
x2 + (y - b)2 = b2 or, equivalently, x2 + y2 - 2by = 0
The line passing through the center of a circle with two endpoints on the circle is the circle's diameter.
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
Equation of circle: (x-3)^2 +(y+5)^2 = 13
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
It is (x + 2)^2 + (y + 3)^2 = 9
Perpendicular to a line passing through the center of the Earth.
A diameter.
9