The general formula: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.
So the required equation of the circle is:
(x - -4)^2 + (y - 0)^2 = 10^2
(x + 4)^2 + y ^2 = 100
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102
The radius of a circle is the distance from the center of the circle to any point on its circumference. In this case, if the circle has a diameter of 20 feet, the radius would be half of that, which is 10 feet. So, the radius of a 20 ft circle is 10 feet.
Endpoints of diameter: (-10, -2) and (4, 6)Midpoint which is the center of the circle: (-3, 2)Radius of the circle: square root of 65Equation of the circle: (x+3)^2 +(y-2)^2 = 65
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
The centre is (3,-1) and the radius is sqrt(10).
Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102
x² + y² = 100.
I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign. This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to: (x - 7)^2 + (y - (-6))^2 = 10^2 And you can directly read off the coordinates of the center (7, -6), and of the radius (10).
If the centre of the circle is at the point (a, b), the equation is: (x - a)2+ (y - b)2= 100.
The radius is half the diameter. The diameter is twice the radius. If the radius is 10 inches, the diameter is twice that, or 20 inches. The radius is any straight line that connects a point on the circle with it's center. The diameter is a line segment that connects two points on a cirle throught the center of the circle.Answer:Let r be the radius of the circle and d be the diameter of the circle. We know that the diameter = 2 * radius of the circle. Given the radius r = 10 inches. Diameter d = 2 * 10 Diameter = 20 inches.
The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)
If you mean (-3, 5) and (5, 11) then using the distance formula the radius of the circle is 10 units
The circumference of a circle can be found using the equation c=2πr. For example, if a circle has a radius of 10, its circumference is 20π, or 62.832.
Circumference = 2*Ï€*radius = 20*Ï€ feet
Since the 2 would be the x in the center coordinate (x,y) and 8 would be the y respectively they would fit into the following equation for a circle as follows: (x-h)^2 + (y-k)^2 = r^2 (x-2)^2 + (y-8)^2 = (square root of 10)^2 Remember that the 2 for the x would become negative because the equation states that the h value becomes negative....same for the y value as well. The final equation after squaring the square root of 10 would be: (x-2)^2 + (y-8)^2 = 10 This would be the final equation of the circle with center (2,8) and radius of root 10. Hope this helped! :) I'd guess that your question involves a circle centered at the cartesian coordinate (2,8): Your standard equation goes as follows: (x-2)2+(y-2)2=10 x2+y2-4x-16y+58=0 for circle with centre at(2,8) and radius the squareroot of 10. (x-2)^2 + (y-8)^2 = 10