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What is the center and radius of a circle with an equation of x squared plus y squared - 10x plus 6y equals 47?
Lovablelauren
The equation of the circle with center (h, k) and radius r is of the form
(x - h)2 + (y - k)2 = r2
x2 + y2 - 10x + 6y = 47 (complete the square)
[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2
(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32
(x - 5)2 + (y + 3)2 = 81
(x - 5)2 + (y + 3)2 = 92
So that the center of the circle is (5, -3) and the radius is 9.
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