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How do you Write the equation of the line that is perpendicular to y 3x plus 8 and passes through the point (-3 4).?
Wiki User
∙ 6y ago
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
Wiki User
∙ 6y ago
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How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
How do you write the equation of the line perpendicular to the line x equals 6 and passing through the point -4 5?
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
What is the equation of a line perpendicular to y equals negative three x plus four that passes through -1 6?
You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
How do you write an equation that is perpendicular to a given line and passes through the given point?
you make an equation of the line: standard form: (y-y1)= m(x-x1) so if the point is (2, -2) and you want to make it perpendicular to the line with a slope (m) of 1/2, the perpendicular slope is the negative recipricle which is -2 so the equation would be: (y--2)= -2(x-2) (y+2)= -2(x-2) y+2= -2x +4 -2 -2 Slope Intercept Form: y= -2x +2
What is an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line?
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
How do you write the equation of the line perpendicular to the line x equals 6 and passing through the point -4 5?
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
Write in slope intercept form the equation of the line that is parallel to the given line and passes through the given point?
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
a line passes through the point (-2,5) and through the point (3,6) write the equation of the line?
sda
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
Is used to write the equation of the line with the given slope that passes through a given pointp?
Coordinate geometry
How do you write the equation of a line that passes through the point 4 and 2 and has a slope of 2?
Y=2x+6
If the equation of a line passes through the points (1, 3) and (0, 0), which form would be used to write the equation of the line?
Slope-intercept form
Write the equation of the line through (2 3) that is perpendicular to y -2x - 2.?
If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4
What is the longest math equation ever?
write a perpendicular 8 and u will get your answer
