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(x-a)^2+(y-0)^2=a^2 here the centre lies on x axis thus the centre wud be a point (a,0) and thus as it passes thru origin radius becomes a. as passes thru (0,0) LHS=(0-a)^2+(0-0)^2=a^2 RHS=a^2

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Q: What is the equation of the circle passing through the origin and having centre at X-axis?
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