Q: What is the equation of the line that passes through (5 -2) and (-3 4)?

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If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x

Y+2 = 2 (x-3)

If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5

Points: (2, -5) and (6, 3) Slope: 2 Equation: y = 2x-9

The equation in slope-intercept form would be y=-2x

Related questions

which equation has a slope of -1/2 and a graph that passes through (-3,4)?

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

The straight line equation is: y = 2x

It is: y = -2x

It is: y = -2x-2

It is y = 2.

3

y - 2 = 0

y - 2 = 0

y - 2 = 0

414

Y=mx+b