If the points are (1,5) and (0,0) y = 5x
8
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
Points: (3, 15) and (5, 9) Slope: -3
If the points are (1,5) and (0,0) y = 5x
8
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
The equation works out as: 5y = 2x or as y = 2/5x
188
Points: (0, 5) and (10, -15) Slope: -2
Points: (3, 15) and (5, 9) Slope: -3
Given any two points, there are infinitely many coplanar circles that can go through the two points. And then each circle can be rotated through infinitely many planes about the straight line joining those two points. So as stated, there is not the slightest hope of pinning down an answer.
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.