If you mean points of: (-1, 5) and (2, -4)
Then the equation works out as: y = -3x+2
If the points are (1,5) and (0,0) y = 5x
8
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
Points: (3, 15) and (5, 9) Slope: -3
If the points are (1,5) and (0,0) y = 5x
8
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
The equation works out as: 5y = 2x or as y = 2/5x
An equation of a line that is parallel to the x-axis is a horizontal line, which has a constant y-value. Since the line passes through the point (15), it must have the same y-coordinate as that point. Therefore, if the point is (15, y), the equation of the line is (y = k), where (k) is the y-coordinate of the point. If the y-coordinate is not specified, the equation can be expressed as (y = b), where (b) is the y-value of the point through which it passes.
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Points: (0, 5) and (10, -15) Slope: -2
Points: (3, 15) and (5, 9) Slope: -3
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
Given any two points, there are infinitely many coplanar circles that can go through the two points. And then each circle can be rotated through infinitely many planes about the straight line joining those two points. So as stated, there is not the slightest hope of pinning down an answer.