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What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?

y = (2/5)x

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Q: What is the equation of the line containing the points 5 2 10 4 and 15 6?
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What is the equation of the line containing the points (5 2) (10 4) and (15 6)?

The equation works out as: 5y = 2x or as y = 2/5x


In what direction is the line containing the points (-10-6) and (-18) going?

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What is the function of the line that contains the points (10-2) and (20-12)?

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What is the equation for a line that passes through the points (-50) and (109)?

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Given points: (6, 11), (3, 10)Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)y - 10 = (1/3)(x - 3)y - 10 = (1/3)x - 1y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1-(1/3)x + y = 9 which is the general form of the required line.


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