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Choose the equation of the line that contains the points (1, -1) and (2, -2).
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
If you mean the slope of the line with equation y = x then it is 1 and there is no y intercept
The straight line equation works out as: 3y = x
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
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The straight line equation is: y = -4x+1
Choose the equation of the line that contains the points (1, -1) and (2, -2).
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
The equation of the line is: y = -x-5
Without an equality sign it is not an equation but if you mean y = 3x-1 then it is a straight line equation
It would be perpendicular to a line with the equation Y = 1/8 X.
The slope of the line is 2 and its equation is y = 2x-1
The equation of a vertical line x = 5 or the equation of a horizontal line y = 5.
The straight line equation is: y = -x-5
If you mean the slope of the line with equation y = x then it is 1 and there is no y intercept
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