x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
7
Since 25 is equal to 52, you can replace 25 by 52 anywhere it appears. 52 = 5 x 5 = 25.
5 times 5 equals 25.
x^5+2x^4+4x^2+2x-3
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.
1.6667
7
The additive inverse is x5 + 2x - 2.
5x + 5y = 5(x+y)
is a quintic expression in x (NOT an equation).
Since 25 is equal to 52, you can replace 25 by 52 anywhere it appears. 52 = 5 x 5 = 25.
x2(x3 + 1) is the best you can do there.
25 Ft2
5 times 5 equals 25.
6 X 5 =30, 30 divided by 3 = 10. 10 divided by 67 = 0.15 (rounded up).