5x2
(5x-6)(x-3)
(5x - 1)(x + 6)
In mathematics, a numerical coefficient is a constant factor in a term of an algebraic expression. For example, in the term 5x, the numerical coefficient is 5. In the expression 2y^2, the numerical coefficient is 2. Numerical coefficients can be positive, negative, integers, fractions, or even irrational numbers.
To factor any term, divide by the LCF (largest common factor) of the term. For 5x2-45, the LCF is 5. 5x2-45 = 5(x2-9) It can, of course, be factored even further to become: 5(x2-9) = 45(x2/9 - 1) but when factoring, we usually don't need to go past 5(x2-9) (for example, you've figured out that x2 = 9, thus x = +/- 3.)
I'm pretty sure you didn't write down the expression to be factored correctly. If you can't do that, neither you nor anybody else will be able to factor your expression.
5x2 + 3x - 1 does not have rational factors.
5(x2 - 25) 5(x + 5)(x - 5)
5x2-46x+9 = (5x-1)(x-9)
5x2 + 20x = 5x (x + 4)
The expression has no rational factors.
5x2-18x+9 = (5x-3)(x-3)
x(5x - 4)
With great difficulty!
5x2
5x2 + x - 6 = (5x + 6)(x - 1) 5x2 - x - 6 = (5x - 6)(x + 1)
The GCF is 5x2