Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
The prime factorization of 48 is 2*2*2*2*3
First, I'll multiply by -1, to make it a little easier to work with (then when done, I'll multiply by -1 again): x2 + 2x - 48. We want two numbers, when multiplied yield -48, and the sum is 2: -6 and 8. (x + 8)(x - 6) works. Now multiply one of the binomial factors by -1: (x + 8)(6 - x). Multiply using FOIL to check: -x2 - 2x + 48
If, perhaps, you meant x^2 - 8x - 48, then the factors are (x - 12) & (x + 4).If you really meant x^8 - 8x - 48, then there are 2 real factors at (x+1.562) & (x-1.673) [Approximate, using numerical means], the other 6 should be complex number factors.
The factors of 48 are 1,2,3,4,6,8,12,16,24 and 48.
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (x +6)(8 - x)
-x2 + 2x + 48 = (-x - 6)(x - 8)
No - the prime factorization for 48 is 24 x 3.
Prime factorization for 48: 2^4*3
The prime factorization of 48 is 2x2x2x2x3, or 24x3 in exponential form.
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
(20x8 + 12x4) over 4x2 = 160 + 48 over 8 = 208 over 8 = [26] OR 20x8 + (12x4 over 4x2) = 160 + (48 over 8) = 160 + 6 = 166
4x2 -26 -48 = 04x2 - 74 = 04x2 = 74x2 = 18.5x = 4.30
The prime factorization of 48 is 2X2x2x2x3.
48 = 2 4 • 3