-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (-x - 6)(x - 8) = -(x + 6)(x - 8)
x2 + 2x - 48 = x2 + 8x - 6x - 48 = x(x + 8) - 6(x + 8) = (x - 6)(x + 8)
5x + 2x + 6 = 48 7x + 6 = 48 ....Because you simplify 5x + 2x 7x = 42 ....Because you subtract 6 from both sides to help isolate x x = 6 ....Because you divide both sides by 7 to isolate the x.
52 = 2x + (6x +4) 52 = 2x + 6x + 4 (can skip this step) 52 = 8x + 4 52 - 4 = 8x 48 = 8x 48/8 = x (can skip this step) 6 = x
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (-x - 6)(x - 8) = -(x + 6)(x - 8)
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
First, I'll multiply by -1, to make it a little easier to work with (then when done, I'll multiply by -1 again): x2 + 2x - 48. We want two numbers, when multiplied yield -48, and the sum is 2: -6 and 8. (x + 8)(x - 6) works. Now multiply one of the binomial factors by -1: (x + 8)(6 - x). Multiply using FOIL to check: -x2 - 2x + 48
The expression is -x² + 2x + 48. Factor out -1 to get: -(x² - 2x - 48) Find two integers such that the product is -48 and the sum is -2. They are -8 and 6. Then, we can rewrite the expression as: -(x² - 8x + 6x - 48) Factoring-by-grouping, we obtain: -(x(x - 8) + 6(x - 8)) = -(x + 6)(x - 8) [Collect x and 6 and group x - 8.]
m² - 14m + 48 = (m - 6)(m - 8)
....................48...................../\...................4 x 12 ................../\ ...../\...............2 x 2 2 x 6............................/\ .........................2x 3 Thus, the prime factorization of 48 is 2x2x2x2x3 or 24x3.
48
x2 + 2x - 48 = x2 + 8x - 6x - 48 = x(x + 8) - 6(x + 8) = (x - 6)(x + 8)
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
5x + 2x + 6 = 48 7x + 6 = 48 ....Because you simplify 5x + 2x 7x = 42 ....Because you subtract 6 from both sides to help isolate x x = 6 ....Because you divide both sides by 7 to isolate the x.