First, I'll multiply by -1, to make it a little easier to work with (then when done, I'll multiply by -1 again): x2 + 2x - 48. We want two numbers, when multiplied yield -48, and the sum is 2: -6 and 8. (x + 8)(x - 6) works. Now multiply one of the binomial factors by -1: (x + 8)(6 - x). Multiply using FOIL to check: -x2 - 2x + 48
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
X2 + 2X - 35(X - 5)(X + 7)================take your pick of these two binomials
10 + 9x
Jjg
6x2-5x-25 = (3x+5)(2x-5) when factored
(2x+7)(x+7)
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (x +6)(8 - x)
-x2 + 2x + 48 = (-x - 6)(x - 8)
2x2+9x+9 = (2x+3)(x+3) when factored
-2x(x + 3)(x - 2)
It is (7x+5)(2x-7) when factored
2x2+21x+49 = (2x+7)(x+7)
2x2 + 15x + 25 = (2x + 5)(x + 5)
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
2x^2
If you mean: 2x2+15x+25 then it is (2x+5)(x+5)