Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
The nth term of the sequence is 3n - 2.
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The nth term of the sequence is expressed by the formula 8n - 4.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The Nth term in the series is [ 2N ] .
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
The nth term of the sequence is 3n - 2.
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
They are: nth term = 6n-4 and the 14th term is 80
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
The nth term of the sequence is expressed by the formula 8n - 4.
-4-14112031 = -14112035 is a single number, not a sequence! It cannot have an nth term.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].