Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
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The given sequence is an arithmetic sequence with a common difference of 2 between each term. The nth term of an arithmetic sequence can be found using the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 2, the common difference (d) is 2, and the nth term can be expressed as (a_n = 2 + (n-1)2 = 2n). So, the nth term of the sequence 2 4 6 8 is (2n).
Oh, dude, it's like super simple. The sequence is just increasing by 2 each time, so the nth term would be 2n. So, like, if you want the 5th term, it would be 2(5) which equals 10. Math is easy when you break it down, man.
The nth term of the sequence is 3n - 2.
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The nth term of the sequence is expressed by the formula 8n - 4.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].