Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
The nth term of the sequence is 3n - 2.
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The nth term of the sequence is expressed by the formula 8n - 4.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The Nth term in the series is [ 2N ] .
The nth term of the sequence is 3n - 2.
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
They are: nth term = 6n-4 and the 14th term is 80
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
-4-14112031 = -14112035 is a single number, not a sequence! It cannot have an nth term.
The nth term of the sequence is expressed by the formula 8n - 4.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.