a^2 - b^2 = (a + b)(a + b).
a^2 - b^2 = (a + b)(a - b)
You can use the formula for factoring the difference of two squares in this case.
x^2 - 64.
Both squares a rhombuses have all equal sides. A square is a rhombus with 4 right angles.
The difference of two squares is quick way to factor polynomials when certain constraints are met: Namely that you have two squares (e.g. 4, 25, 36x2 , 144a6) and one is subtracting from the others (e.g. 25 - 36x2). IF these two constraints are met, then you are able to factor the polynomial by finding the square roots of the squares. sqrt(25)=5 sqrt(36x2) = 6x Therefore 25 - 36x2 = (5+6x)(5-6x) in factored form. In general, given any two squares, a2 and b2, AND they are subtracting, a2 - b2, you can factor them to be (a + b)(a - b).
Their sum and their difference.
For the difference of squares to apply, the expression must be in the form (a^2 - b^2), where both (a) and (b) are real numbers. Additionally, (a) and (b) must be perfect squares, meaning they can be expressed as squares of other real numbers. Lastly, the subtraction must be between these two squares, ensuring that it is indeed a difference.
a^2 - b^2 = (a + b)(a - b)
A difference of two squared terms, i.e.:a2 - b2This form can be factored into (a + b)(a - b).
There is a formula for the "difference of squares." In this case, the answer is (8x + 7)(8x - 7)
difference of squares if something of the form a^2-b^2. So for example x^2-y^2 since both are squares. The value in looking at these is that we can factor a^2-b^2 in (a+b)(a-b)
The difference of 2 squares ca n be expressed as: x2 - y2
All terms have even powers, factorable to the form (a+b)(a-b)
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GFYM
The difference of two squares which enables complex conjugates to be used.The difference of two squares which enables complex conjugates to be used.The difference of two squares which enables complex conjugates to be used.The difference of two squares which enables complex conjugates to be used.
How can you have 0 as the difference of two squares? 5^2-5^2?