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The difference of 2 squares ca

n be expressed as: x2 - y2

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12y ago

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How do you write 0 as the difference of two squares?

How can you have 0 as the difference of two squares? 5^2-5^2?


What 3 things must be true for difference of squares apply?

For the difference of squares to apply, the expression must be in the form (a^2 - b^2), where both (a) and (b) are real numbers. Additionally, (a) and (b) must be perfect squares, meaning they can be expressed as squares of other real numbers. Lastly, the subtraction must be between these two squares, ensuring that it is indeed a difference.


What is an difference of square?

difference of squares if something of the form a^2-b^2. So for example x^2-y^2 since both are squares. The value in looking at these is that we can factor a^2-b^2 in (a+b)(a-b)


What is the form of the Difference of Squares identity?

a^2 - b^2 = (a + b)(a + b).


What is the factor form of the difference of the two squares?

a^2 - b^2 = (a + b)(a - b)


What is a difference of squares that has a factor of x 8?

x^2 - 64.


What are binomial differences?

The difference of two squares: 4 -9 = (2-3)(2+3)


Which of the following is not a difference of two squares?

The one that doesn't follow the pattern of a^2 - b^2.


How would you factorise x2-49?

To factorise ( x^2 - 49 ), you can recognize it as a difference of squares. This expression can be rewritten as ( (x)^2 - (7)^2 ). Using the difference of squares formula, ( a^2 - b^2 = (a - b)(a + b) ), we factor it as ( (x - 7)(x + 7) ).


What is the difference of squares of 2m2 - 8?

2m2 - 8 = 2(m2 - 4) = 2(m + 2)(m - 2)


What is the square of a minus b?

It depends what you mean.a2-b2 is the difference of two squares so it equals (a-b)(a+b) (a-b)2=a2-2ab+b2if your question is a difference of squares and it looks like (a-b)^2, then your answer is (a+b)(a-b).


How do you factor a4 - b4 completely?

To factor a^4 - b^4 completely, you can use the formula for the difference of squares, which states that a^2 - b^2 = (a + b)(a - b). In this case, a^4 - b^4 is a difference of squares twice: (a^2)^2 - (b^2)^2. So, you can factor it as (a^2 + b^2)(a^2 - b^2). Then, factor a^2 - b^2 further using the difference of squares formula to get (a^2 + b^2)(a + b)(a - b), which is the complete factorization of a^4 - b^4.