The difference of 2 squares ca
n be expressed as: x2 - y2
How can you have 0 as the difference of two squares? 5^2-5^2?
For the difference of squares to apply, the expression must be in the form (a^2 - b^2), where both (a) and (b) are real numbers. Additionally, (a) and (b) must be perfect squares, meaning they can be expressed as squares of other real numbers. Lastly, the subtraction must be between these two squares, ensuring that it is indeed a difference.
The one that doesn't follow the pattern of a^2 - b^2.
To factorise ( x^2 - 49 ), you can recognize it as a difference of squares. This expression can be rewritten as ( (x)^2 - (7)^2 ). Using the difference of squares formula, ( a^2 - b^2 = (a - b)(a + b) ), we factor it as ( (x - 7)(x + 7) ).
2m2 - 8 = 2(m2 - 4) = 2(m + 2)(m - 2)
How can you have 0 as the difference of two squares? 5^2-5^2?
For the difference of squares to apply, the expression must be in the form (a^2 - b^2), where both (a) and (b) are real numbers. Additionally, (a) and (b) must be perfect squares, meaning they can be expressed as squares of other real numbers. Lastly, the subtraction must be between these two squares, ensuring that it is indeed a difference.
difference of squares if something of the form a^2-b^2. So for example x^2-y^2 since both are squares. The value in looking at these is that we can factor a^2-b^2 in (a+b)(a-b)
a^2 - b^2 = (a + b)(a + b).
a^2 - b^2 = (a + b)(a - b)
x^2 - 64.
The difference of two squares: 4 -9 = (2-3)(2+3)
The one that doesn't follow the pattern of a^2 - b^2.
To factorise ( x^2 - 49 ), you can recognize it as a difference of squares. This expression can be rewritten as ( (x)^2 - (7)^2 ). Using the difference of squares formula, ( a^2 - b^2 = (a - b)(a + b) ), we factor it as ( (x - 7)(x + 7) ).
2m2 - 8 = 2(m2 - 4) = 2(m + 2)(m - 2)
It depends what you mean.a2-b2 is the difference of two squares so it equals (a-b)(a+b) (a-b)2=a2-2ab+b2if your question is a difference of squares and it looks like (a-b)^2, then your answer is (a+b)(a-b).
To factor a^4 - b^4 completely, you can use the formula for the difference of squares, which states that a^2 - b^2 = (a + b)(a - b). In this case, a^4 - b^4 is a difference of squares twice: (a^2)^2 - (b^2)^2. So, you can factor it as (a^2 + b^2)(a^2 - b^2). Then, factor a^2 - b^2 further using the difference of squares formula to get (a^2 + b^2)(a + b)(a - b), which is the complete factorization of a^4 - b^4.