Area of rod = length*diameter*pi
pi*radius2*length in cubic units
a fission rod (fishing rod)
Pythagoras! length = sqrt (7 squared + 30 squared) ie sqrt 949 ie 30.81 cm
Aluminum is a bit more difficult to weld than steel , because of it's lower melting point. Also Aluminum takes more heat , because of it's property of absorbing and releasing the heat quicker. With the proper electrode , or rod , and amps to volt settings, along with a bit of practise , it can be quite simple . One usually has to have a faster travel speed with the filler rod or electrode.
If the rod has a radius of R and a length of L, then total area = 2*pi*R*(R+L) square units.
First, you need to know the mass of brass: Brass, Specific Gravity 8.56 lb per Cubic Foot (from wikianswers) second: you need to know the length and radius of the rod. formula: divide the radius of the rod by two square the answer you get (multiply it by itself) multiply by pi You have now calculate the area of the rod's end. multiply the answer by the length of the rod and you get the volume of the rod finally, multiply the answer by the specific gravity for brass. The answer is the weight of the brass rod NOTE: make sure you use the same units for length and mass throughout the formula. In the above example you will have to know the radius and length in feet to yield the weight in lbs. If you want to know the answer in a different unit (ounces for example) you will have to convert the specific gravity to correct units.
Im not sure what you mean by a pure rod, but if you are talking about a solid rod, which is simply a cylinder, you can calculate its area as follows: πDL+(πR²)2 Which is pi times the diameter times the length plus pi times the radius squared multiplied by 2.
pi*radius2*length in cubic units
i'am not sure if the radius rod and radius bar are the same on a twin i- beam truck
If the steel rod has a circular cross-section - the usual case - you can use the formula for a cylinder. Since the area of the base is quite small, it can be ignored - just calculate length x diameter x pi.
at o.75 of the height of cylinder (or length of the rod)
radius=12.4+/-0.5mm length=243.3+/-0.5mm 1)length+width (12.4+/-0.5mm)+(243.3+/-0.5mm) (12.4+243.3)+/-(0.5+0.5) 255.7+/-o.1 2)length-width (243.3-12.4)+/-(0.5+0.5)mm 230.9+/-0.1
Depends on the material density, iron is roughly 8 (g /cm^3), multiply this by the volume to get mass, volume in this case = area * length area = pi * radius squared = 3.14159 * 1.05 * 1.05 = 3.464 cm ^2 volume = area * length = 3.464 * 91.2 = 315.92 cm ^3 volume times density = mass, in this case 315.92 * 8 = 2527.36 grams
6.2
Formula of hexagonal ms rod
welding rod chemical formula?