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Call the relation R. Also, x R y means (x, y) is in R. (For an idea of how that works, in the set called <, the first element of each ordered pair is always smaller than the second.) Now, a relation is reflexive if, for all x in the domain of R, x R x. That is, (x, x) is in R. A few examples are =, ≤, | (or, "is divisible by"), and the ever familiar, "plus some integer equals."

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Q: What is the formula of reflexive relation?
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Related questions

Give an example to a relation which is reflexive symmetric but not transitive?

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No. Do your own homework. http://docs.google.com/gview?a=v&amp;q=cache:ZZmsH0jKHH8J:www.cs.utk.edu/~horton/hw1.pdf+For+each+part+give+a+relation+that+satisfies+the+condition+a+Reflexive+and+symmetric+but+not+transitive+b+Reflexive+and+transitive+but+not+symmetric+c+Symmetric+and+transitive+but+not+reflexive%3F&amp;hl=en&amp;gl=us&amp;sig=AFQjCNHGyc1EDhfqj_mu-RV9yTYZZfXl6A


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A c program to find an entered relation is equivalence relation or not?

void reflexive(int a[], int sizeOfA, int b[], int sizeOfB) { bool hold = true; for(i = 0; i &lt; sizeOfA &amp;&amp; hold; ++i ) { for( int j = 0; j &lt; sizeOfB &amp;&amp; hold; ++j ) { int elemA = a[i]; int elemB = b[i]; if(a[i] == b[i]) { hold = true; break; } } if(hold == false) { cout &lt;&lt; "Reflexive - No" &lt;&lt; endl; break; } } if(hold == true) cout &lt;&lt; "Reflexive - Yes" &lt;&lt; endl; }