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Cannot tell whether the equation was
y = -4x + 3
y = -4x - 3
y - 4x = 3
or something else.
y=-4x + 3 or generally y=mx + b so m, or gradient = -4
4x-y+3 = 0 -y = -4x-3 y = 4x+3 Therefore: the slope is 4 and the y intercept is 3
If you mean: y = -4x+3 then the perpendicular slope is 1/4
If you mean: y = -4x+3 then the parallel equation will have the same slope but a different y intercept
2y=4x+1 sp y=2x+1/2 so the slope or gradient is 2
If you mean y = -4x+3 then the gradient of the line is -4 and the y intercept is 3
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
y=-4x + 3 or generally y=mx + b so m, or gradient = -4
2y = 6 4x y=3 + 2x y= 2x + 3
parallel to y=4x-3 so they have the same gradient of 4 y intercept is positive 1 so y=4x+1
y = -4x
3
1
4x + y + c = 0 or, for a line going through a given point (xo, yo): y + 4x - (xo + yo) = 0 The gradient of a line multiplied by the gradient of a line perpendicular to it is -1; or in other words: The gradient of the perpendicular line is the negative reciprocal of the gradient of the line. Thus: 2x - 8y + 23 = 0 ⇒ 8y = 2x + 23 ⇒ y = 1/4x + 23/8 ⇒ gradient of perpendicular line is -1 ÷ 1/4 = -4 Thus the equation of the perpendicular line to 2x - 8y + 23 = 0 is 4x + y + c = 0. To find the line through point (xo, yo) perpendicular to 2x - 8y + 23 = 0, use the format: y - yo = m(x - xo) ⇒ y - yo = -4(x - xo) ⇒ y + 4x - (xo + yo) = 0
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
3y - 4x = 24 The first step is to write it in the standard form (y=mx + c) 3y = 4x + 24 y = (4x + 24)/3 y = 4x/3 + 8 The y-intercept is 8 and the slope/gradient is 4/3
4x-y+3 = 0 -y = -4x-3 y = 4x+3 Therefore: the slope is 4 and the y intercept is 3