If you're weighing, about 0.04 or less.
g^4 - 9
3x+5
Unless you have a value for x, it cannot be simplified any further so it will be: x - 9
If f(x)=2z^2+5 and g(x)=x^2-2, fine (f-g)(x)
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
0.0005 g0.1 g0.005 g0.001 g
9000 g = 9 kg9000 g = 9 kg9000 g = 9 kg9000 g = 9 kg9000 g = 9 kg9000 g = 9 kg
Since g is given to 2 decimal places you can assume that g is rounded to the hundredths place. That means the maximum ABSOLUTE error in g is 0.005 metres/sec2. The percentage error, is 100*(0.005/9.81) = 0.051 (approx)
9 g x 1000 mg/g = 9,000 mg in 9 g
9 kg is greater than 90 g.9 kg = 9000 g > 90 g
The greatest common multiple of any set of integers is infinite.
No, 198 g is not to 9 kg.198 g is equal to 0.198 kg.9 kg is equal to 9000 g.
9 kg 20 g = 9020 g
g^4 - 9
4
G
If you take four consecutive numbers, for example, 27, 28, 29, and 30, then 27/3 = 9, 28/3 = 9 remainder 1, 29/3 = 9 remainder 2, 30/3 = 10. Therefore, the greatest remainder you can get when dividing by 3 is 2.