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To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.

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What is the height of a flagpole if a person 5 feet tall casts a 10 foot shadow at the same time that the flagpole casts a 40 foot shadow?

The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.


A 3 foot pole casts a 6 foot shadow A 4 foot pole casts an 8 foot shadow Use a linear equation to predict the length of a shadow cast by a 6 foot pole?

Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.


The shadow cast by a house is 55 feet long.At the same time a flagpole that is 15 feet tall casts a 25 foot long shadow.How tall is the house?

25


If a 30 foot flagpole casts a 12 foot shadow how tall is a mailbox casting a 18 inch shadow?

First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in


How high is a tree that casts a 21 foot shadow at the same time a 6.5 foot man cast a 5 foot shadow?

27.3 feet

Related Questions

What is the height in feet of a flagpole which casts a 6-foot shadow when a 6-foot man cast a 3-foot shadow?

Using trigonometry its height is 12 feet


If a 30 foot flagpole casts a12 foot shadow how tall is a mailbox casting a 18 inch shadow?

It works out as 3.75 feet


What is the height of a flagpole if a person 5 feet tall casts a 10 foot shadow at the same time that the flagpole casts a 40 foot shadow?

The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.


How high is a tree that's casts a ft shadow at the same time a ft pole casts a shadow which is ft long?

To determine the height of the tree based on the shadow length, we can use the concept of similar triangles. If the tree casts a shadow of 1 foot while a 1-foot pole also casts a shadow of 1 foot, then the height of the tree is the same as the height of the pole. Thus, the tree is also 1 foot tall.


A tree is 18 feet tall and casts a shadow 6 feet long A nearby sign casts a 3 foot shadow What is the height of the sign?

A 1 foot shadow I think.


What is the angle of elevation to the nearest degree of the sun if a 54 foot flagpole casts a shadow 74 feet long?

36 degrees


What is the height of a telephone pole that casts a shadow of 15 feet if a 6 foot tall man casts a shadow of 3.5 feet?

2


A 60-foot -tall flagpole casts a 42-foot long shadowat the same time of daywhat would be the length of a shadow cast by an 18-foot-tall building?

The lenght of the shadow will be 12.6 ft


How high is a tree that casts a 37 ft shadow at the same time a 4foot pole casts a 12 foot shadow?

It works out as 12 feet and 4 inches in height


A 3 foot pole casts a 6 foot shadow A 4 foot pole casts an 8 foot shadow Use a linear equation to predict the length of a shadow cast by a 6 foot pole?

Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.


If an electrical tower casts a foot shadow at the same time a foot street sign casts a shadow of 8 feet then what is the length of the tower?

The lengths of the objects are proportional to the lengths of their shadows, given that they are illuminated by the same light source. If the street sign is 1 foot tall and casts an 8-foot shadow, the ratio is 1:8. Therefore, if the electrical tower casts a 1-foot shadow, it can be calculated as follows: ( \text{Height of tower} = \frac{1 \text{ foot}}{8 \text{ feet}} \times 8 \text{ feet} = 8 \text{ feet} ). Thus, the height of the electrical tower is 8 feet.


The shadow cast by a house is 55 feet long.At the same time a flagpole that is 15 feet tall casts a 25 foot long shadow.How tall is the house?

25