To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
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First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in
27.3 feet
Using trigonometry its height is 12 feet
It works out as 3.75 feet
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
To determine the height of the tree based on the shadow length, we can use the concept of similar triangles. If the tree casts a shadow of 1 foot while a 1-foot pole also casts a shadow of 1 foot, then the height of the tree is the same as the height of the pole. Thus, the tree is also 1 foot tall.
A 1 foot shadow I think.
36 degrees
2
The lenght of the shadow will be 12.6 ft
It works out as 12 feet and 4 inches in height
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
The lengths of the objects are proportional to the lengths of their shadows, given that they are illuminated by the same light source. If the street sign is 1 foot tall and casts an 8-foot shadow, the ratio is 1:8. Therefore, if the electrical tower casts a 1-foot shadow, it can be calculated as follows: ( \text{Height of tower} = \frac{1 \text{ foot}}{8 \text{ feet}} \times 8 \text{ feet} = 8 \text{ feet} ). Thus, the height of the electrical tower is 8 feet.
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