It works out as 3.75 feet
Ten is to two as 40 is to x, yielding: 200ft.
84 feet tall
35 feet tall.
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
To solve this problem, we can set up a proportion using the similar triangles formed by the flagpole and its shadow, and the mailbox and its shadow. The height of the flagpole to its shadow is 30 feet to 12 feet, which simplifies to 5:2. Using this ratio, we can determine the height of the mailbox by setting up the proportion 5/2 = x/1.5 (converting 18 inches to feet). Solving for x, the height of the mailbox would be 3.75 feet.
It works out as: 42.353 feet tall rounded to 3 decimal places
The flagpole is 15.92 metres, approx.
40 meters
21 ft how is the equation to give you this result
It is approx 36.6 ft.
84 feet tall
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
28 feet
The flagpole is 24 feet tall.Assuming their shadows align exactly, they form similar triangles andh/32 = 6/8Mutiply both sides by 32h = 192/8 = 24