It works out as 3.75 feet
Ten is to two as 40 is to x, yielding: 200ft.
84 feet tall
35 feet tall.
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in
It works out as: 42.353 feet tall rounded to 3 decimal places
The flagpole is 15.92 metres, approx.
40 meters
21 ft how is the equation to give you this result
It is approx 36.6 ft.
84 feet tall
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
28 feet
It is known as an eclipse. If the moon is casting a shadow on Earth, it is a solar eclipse. If the Earth is casting a shadow on the moon, it is a lunar eclipse.