So y = (3x - 4)/2. To find the find the inverse equation, y-1,(1) Rewrite the equation replacing all ys with xs and all xs with ys.x = (3y - 4)/2(2) Solve the new equation for yx = (3y - 4)/22x = 3y - 42x + 4 = 3y(2x + 4)/3 = yThis is your inverse equation!y-1 = (2x + 4)/3
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
2x+4 = -16 2x = -16-4 2x = -20 x = -10
2x + 4 = 10 2x = 10 - 4 = 6 2x = 6 x = 6/2 = 3
A reciprocal function will flip the original function (reciprocal of 3/5 is 5/3). An inverse function will change the x's and y's of the original function (the inverse of x<4,y>8 is y<4, x>8). Whenever a function is reflected over the line y=x, the result is the inverse of that function. The y=x line starts at the origin (0,0) and has a positive slope of one. All an inverse does is flip the domain and range.
To find the inverse of a function, you replace x with y and y with x. Here, y=2x-4 would become x=2y-4. Now, we solve for y. 2y=x+4. y=(x/2)+4, and that is the inverse equation.
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
The inverse for f(x) = 4x + 8 isg(x) = x/4 - 2
Yes.
You cannot because the function is not well-defined. There is no equality symbol, the function In(2x) is not defined.
Well, it would be hard to write an inverse function of -4, since -4 is not a function in the first place.
8x-4
x equals 4
1
2x+4+7x-4 is the same as 9x
-2x^4+16 +2x^4+9-3x^5=-3x^5+25. There is no "answer" because there is no equation.
f(x) = (2x^2 + 5x - 12)/(x + 4) as given, is not defined when the denominator is 0 ie when x + 4 = 0 or x = -4. However, 2x^2 + 5x - 12 = (x + 4)*(2x - 3) so that the function can be simplified to (x + 4)*(2x - 3)/(x + 4) = 2x - 3 This has a zero when 2x - 3 = 0 ie 2x = 3 or x = 1.5