f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
y = 3x + 8Replace x with y and y with x.x = 3y + 8Solve for y.x - 8 = 3y3y = x - 8y = (x-8)/3
y = x² - 2x - 8 Swap x and y to find the inverse: x = y² - 2y - 8 Now get y by itself: y² - 2y = x + 8 (Complete the square): y² - 2y + 1 = x + 9 (y - 1)² = x + 9 y - 1 = ±√(x + 9) y = 1 ±√(x + 9) Then there are two functions: f(x) = 1 - √(x + 9) and f(x) = 1 + √(x + 9) but an inverse can only be one function. The functions above are a mirror image of the original function, but it is not an inverse (graph these functions). There is no inverse. Everything above is completely wrong. This is the inverse: (x+8)/2 I don't know where the x² came from in the first answer, but to work out the question as asked: if y=2x-8 y+8 = 2x (y+8)/2 = x so, as the above answer stated, (x+8)/2 is the answer.
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
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y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
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3x-y=9 y=3x-9
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If you mean: y-2 = 3x+2 then as a straight line equation it is y = 3x+4
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
3x-6y=9 -3x -3x -6y=9-3x __ ____ -6 -6 y=9-3x ____ -6
-9
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
(3x - y + 9)(3x - y - 9)