3x-3x+4x^2+8x=4x^2+8x
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.
y=2x+4 --> x=2y+4 ==> y=(x-4)/2
So y = (3x - 4)/2. To find the find the inverse equation, y-1,(1) Rewrite the equation replacing all ys with xs and all xs with ys.x = (3y - 4)/2(2) Solve the new equation for yx = (3y - 4)/22x = 3y - 42x + 4 = 3y(2x + 4)/3 = yThis is your inverse equation!y-1 = (2x + 4)/3
2(3x + 4) + 5x - 2
y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
This is only half of an equation. If -x^2 + 3x +2y = 0, then x^2 -3x = 2y and y = (x^2-3x)/2 Solving for x is the inverse, but difficult without a second equation.
x^2 + 3x - 2; -x^2 - 3x + 2andx - 1; 1 - x
8
It could be a function or a linear expression.
Yes.
y = (4x+9)/(2x+3)2xy+3y = 4x+93y-9 = 4x-2xy3y-9 = x(2-2y)x = (3y-9)/(2-2y)So, inverse function is 3x minus 9 divided by 2 minus 27.
The inverse of a function (G(x)) can be found by switching the roles of (x) and (y) and solving for (y). Given the function (G(x) = -\frac{4}{3}x + 2), let's find its inverse: Step 1: Replace (G(x)) with (y): [y = -\frac{4}{3}x + 2] Step 2: Swap (x) and (y): [x = -\frac{4}{3}y + 2] Step 3: Solve for (y): [x - 2 = -\frac{4}{3}y] [-\frac{3}{4}(x - 2) = y] So, the inverse function (G^{-1}(x)) is: [G^{-1}(x) = -\frac{3}{4}(x - 2)]
3x + 2 = 3x + 6 This is not possible.
3x+2.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x-3x+4x^2+8x=4x^2+8x