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It should be 12882 if I calculated correctly. However I cannot show you how I got the answer here because of the limited mathematical symbols input here. The steps involve using sigma with upper and lower limits. If you want to see my work, visit quickanswerz.com and post this same question there and I can show you exactly how it's worked out!
The even number starts with 2 and goes on.
2, 4, 6, 8… It forms a sequence with the first term 'a' is 2 and the common difference 'd' is 2. We need to find the sum of the first 113 consecutive even numbers. Sum of n terms in a sequence is given by the formula Sn = (n/2) (a + l) (Where 'a' is the first term of the sequence and 'l' is the last term of the sequence.) First, we need to find the last term of the sequence. We know that the nth term of a sequence is given by the formula tn = a + (n-1) d So, t113 = a + (113-1) d. Substitute the value of a and d in the above equation. t113 = 2 + (113-1) 2 = 2 + (112) 2 t113 = 2 + 224. t113 = 226. So, the last term l is 226. Now, substitute all the values in the formula Sn = (n/2) (a + l). Sn = (113/2) (2 + 226) Sn = (113/2) (228) Sn = (113) (114) Sn = 12882 So, the sum of the first 113 consecutive integers is 12882. Source: www.icoachmath.com Option 2 An easier solution would be to use the formula N(N+1), where N is the number of consecutive even numbers. Eg: sum of 113 consecutive even integers would be = 113* 114 = 12882. Use this formula to calculate the sum of consecutive even numbers starting from 2. If the number starts from the middle (20,22,24,26) you need to use Option 1 to find the solution.
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What are three consecutive numbers that add up to 339?
112, 113, and 114
What are three consecutive natural number for 336?
111, 112 and 113.
What three consecutive numbers added together equal 339?
112, 113, 114 The middle number is always a third of the total. The others are one less and one more.
The first five prime numbers between 100 and 200?
The first five prime numbers between 100 and 200 are: 101 103 107 109 113.
What are the first 2 prime numbers after 100?
101 and 103 then 107 109 113 127 and so on ...
What 3 consecutive numbers add up to 342?
113, 114, 115
What are three consecutive numbers that add up to 339?
112, 113, and 114
Three consecutive numbers that have a product of 336?
111 + 112 + 113 = 336
What are three odd consecutive integers that equal 339?
The numbers are 111, 113 and 115.
Find 5 consecutive numbers that add up 555?
560
Find two consecutive positive numbers such that the sum of their square is 113?
Ans - 7and 8
What 5 consecutive numbers add up to 555?
560
Are 113 and 127 twin primes?
No. Twin primes are two consecutive odd numbers that are prime, such as 17 and 19.
What are seven consecutive numbers that add up to 777?
108 109 110 111 112 113 114
What three consecutive odd numbers that have the sum of 339?
Let 'n' be the first odd number,. Then n+ 2 & n + 4 are the second and third odd number. Hence n + (n+2) + ( n + 4) = 339 Add 3n + 6 = 339 3n = 333 n = 111 n + 2 = 113 n + 4 = 115 Hence the three odd consecutive numbers are 111,113 & 115.
Which numbers have the absoulute value of 113?
-113 and +113
What two numbers can be multiplied to get 113?
They are: 1*113 = 113
