To find the last digit of 373^333, we need to look for a pattern in the units digit of the powers of 3. The units digit of powers of 3 cycles every 4 powers: 3^1 = 3, 3^2 = 9, 3^3 = 7, 3^4 = 1, and then it repeats. Since 333 is one less than a multiple of 4, the units digit of 3^333 will be the third number in the cycle, which is 7. Therefore, the last digit of 373^333 is 7.
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answer is 3
sol:
always divide power by 4 so here 333/4=83 and remainder is 1
then we take unit digit of the number which is 373 unit digit is 3
now 3^1 is 3 so units digit of 373^333 is 3
Oh, dude, the last digit of 373,333 is 3. Like, you just look at the number and chop off all the digits except the last one. It's like the number's way of saying, "Hey, I'm ending on a 3, deal with it."
Oh, isn't that a happy little number! If we take a look at 373,333, we can see that the last digit is 3. Just like a little squirrel hiding in the forest, that 3 is there to bring a smile to your face.
To find the last digit of a number raised to a power, we can use the concept of modular arithmetic. The last digit of 333 to the power of 444 can be determined by finding the remainder when 333 is divided by 10, which is 3. Since the last digit of 333 is 3, we need to find the remainder of 444 divided by 4, which is 0. Therefore, the last digit of 333 to the power of 444 is the same as the last digit of 3 to the power of 4, which is 1.
333
333 3 11 111
The answer is 333. Homework,yeh
There need not be any estimated digit but, if there must be one, then it is the last digit: 3.