To find the units' digit of 3 to the power of 333, we need to look for a pattern. The units' digit of powers of 3 cycles in a pattern: 3, 9, 7, 1. Since 333 divided by 4 leaves a remainder of 1, the units' digit of 3 to the power of 333 will be the first digit in the pattern, which is 3.
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3^333 ~ 7.61e+158 and is beyond the range of most calculators. I think "0" would be in the unit digit place.
999 is 333 :) (dividedby three)
3
Power 2: units digit 9. Multiply by 49 again to get power 4: units digit 1. So every 4th power gives units digit 1. So 16th power has units digit 1, so the previous power, the 15th must have units digit 3.
3
In the number 53, the digit 3 holds a place value of 3 units. This means that the digit 3 represents three single units in the number 53. It is important to note that the value of a digit in a number is determined by its position or place value within the number.