20 ft * 28 ft = 560 sq ft = 52.03 sq metres.
Multiply the length of the room times the width.
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
You would multiply the length with the width so 5 feet can be the width and 3 feet can be the length. 5x3=15 s/f
4356 sq ft is 10% of 1 acre.
1 yard = 3 ft so 1 sq yard = 3 ft * 3 ft = 9 sq ft Then 4356 sq ft = 4356/9 = 484 sq yard
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
4356 = 0.1 acres.
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
what is the length x width of a rectangle swimming pool that is 13300 sq ft
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length * Width 300 sq ft = L ft * W ft So W = 300/L ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
By multiplying its length to its width. Area= length x width
volume_cuboid = length × width × height = 4 ft × 2.3 ft × 5 ft = 46 cu ft surface_area_cuboid = 2 × (length × width + width × height + height × length) = 2 × (4 ft × 2.3 ft + 2.3 ft × 5 ft + 5 ft × 4 ft) = 2 × (9.2 sq ft + 11.5 sq ft + 20 sq ft) = 2 × 40.7 sq ft = 81.4 sq ft
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft