Choose ANY positive number of feet for the length. Divide 4356 by that number, to get the width.
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20 ft * 28 ft = 560 sq ft = 52.03 sq metres.
Multiply the length of the room times the width.
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
You would multiply the length with the width so 5 feet can be the width and 3 feet can be the length. 5x3=15 s/f