The garden's diagonal is 10 meters.
20m
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
Each side of a square with an area of 40 acres is 1,320 feet (1/4 mile) long. The diagonal measurement is 1,867 feet long.
Divide the length of the garden into its area to find the width of the garden
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.
The diagonal of the garden is 20 meters.
20m
It is 10 metres.
The diagonal is 10 metres.
The area is 12.5 m2
First, take the square root of 128 to find the side length. Use this with the Pythagorean theorem (a2 + b2 = c2) to find the length of the diagonal, which is the hypotenuse of a triangle that takes up half the area of the whole garden. The diagonal ends up being 16 m. The steps are a bit hard to write on this page, so I've included them in the "related links" section, below.
If the area of the square is 200, then the side is sqrt(200).The length of the diagonal is sqrt(200 + 200) = sqrt(400) = 20 meters.
The diagonal is 14.142 feet.
The diagonal is 33.941 units.
The diagonal is about 16.97 inches long.
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
324 units