The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
15/3=5 equilateral triangle is a triangle with every side the same length
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
3 inches, an equilateral triangle has equal side lengths and angle measures
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Here are a couple Find the altitude of a triangle with base 3 and hypotenuse 5. Find the altitude of an equilateral triangle with each side to 2
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
If the length of a side of an equilateral triangle = 8√3, then the altitude bisects the base forming a right angled triangle. The side measuring 8√3 is the hypotenuse, the altitude (A) is one leg and half the base length is the second leg. By Pythagoras, (8√3)2 = (4√3)2 + A2 : A2 = (64 x 3) - (16 x 3) = 48 x 3 = 144 Therefore the altitude, A = √144 = 12
Side = 6 cm 1/2 of the base = 3 cm Altitude = 3 times square-root of 3 = 5.196 cm (rounded)
15/3=5 equilateral triangle is a triangle with every side the same length
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.