20 inches
For rectangles, the longest sides are always the 'length' measurement.
Width = 9 inches Length = 30 inches
A square has equal length and width. The length would be 3.75 inches.
Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2
Perimeter = 5*26 = 130cm Missing length = 130-23.3-30.4-44.9 = 31.4cm
n:8 15:10 n=12
If the 'ratio' (length/width) of one rectangle is the same number as (length/width) of the other one, then the two rectangles are similar.
Do you mean the surface area of the box? If so... What you do is break the surface area into 6 rectangles: Two rectangles have sides of length 6.3 and 12.6 inches. Two rectangles have sides of length 6.3 and 4.2 inches. Two rectangles have sides of length 12.6 and 4.2 inches. Find the area of each of the six rectangles (using the standard formula for the area of a rectangle, A = W x H), and add up all six. The sum of the areas of the six rectangles will be the surface area of the box. Since the lengths of the sides are in inches, the area will already be in square inches, and therefore you don't have to "turn it into square inches".
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
Every rectangle is similar in that they both have 4 sides, they both have 4 angles, and they both have 2 sides equalling one length and the other 2 sides equalling a shorter length. Every two rectangles are similar in a way but they are not all exactly the same.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
DICK
The exact answer cannot be given because the number of inches for the length is missing. But if it was k inches, the width would be 375/k inches.
8:32
It is 64 square inches.
If you are given two similar rectangles, one with all measurements and the other with only one, you first need to find the conversion ratio. Let's call the rectangle that you know everything about, rectangle A, and the other rectangle B. You take the ratio of the side of rectangle B to rectangle A. You then multiply the length of rectangle A by this value, to find the length of rectangle B.
yes they can the square could have a side of sqrt of 50 inches just multiply that by itself and you have 50sq inches the rectangles could have a length of 5 and a length of 10. multiply them to gether and y ou have 50sq in