Let's lay out the known information in equations, where B is the number of boys and G is the number of girls. Then we express the number B in terms of G, which is twice as much less 12, or (2G-12) B + G = 51 , and B = 2G - 12 Now, replace the B in the first equation with its value from the second equation (2G - 12) + G = 51 Remove the brackets 2G - 12 + G = 51 Add 12 to both sides 2G + G = 51 + 12 3G = 63 Divide both sides by 3 G = 21 Now, to check if we're right, Replace G in the first equation B + 21 = 51 B = 30 If that's right then 30 = 2(21) - 12 30 = 42 - 12 And it is, so we know that there are 21 girls and 30 boys in ninth grade.
Points: (-12, -17) and (21, 5) Slope: 2/3
One fourth of 8 is 2.
hmm... i don' think you have the completed the question. This one is pretty hard! Solving quadratics can be difficult and ompleting the square is one method for solving a quadratic equation.Is the equation -84x2-8x-12=0 or -84x2+8x - 12 = 0 or -84x2 = 8x - 12?If it is the first one:Factor out the 4:-4 (21x2 + 2x + 3) = 021x2 + 2x + 3 = 0 (divide by 21 each term to both sides)x2 + (2/21)x + 3/21 = 0 (subtract 3/21 to both sides)x2 + (2/21)x = -3/21 (add (1/2 of 2/21)2 or (1/21)2 to both sides)x2 + (2/21)x + (1/21)2 = -3/21 + 1/212(x + 1/21)2 = -63/212 + 1/212(x + 1/21)2 = -62/212 (square root to both sides)x + 1/21 = ± √-62/212x + 1/21 = ± (i/21)√62 (subtract 1/21 to both sides)x = -1/21 ± (i/21)√62x = -1/21 (1 - i√62) orx = -1/21 (1+ i√62)If it is the third one:-84x2 = 8x - 12 (divide by -84 to both sides)x2 = -(2/21)x + 3/21 (add (2/21)x to both sides)x2 + (2/21)x = 3/21 (add (1/2 of 2/21)2 or (1/21)2 to both sides)x2 + (2/21)x + (1/21)2 = 3/21 + 1/212(x + 1/21)2 = 63/212 + 1/212(x + 1/21)2 = 64/212 (square root to both sides)x + 1/21 = ± √64/212x + 1/21 = ± 8/21 (subtract 1/21 to both sides)x = -1/21 ± 8/21x = -1/21 + 8/21 = 7/21 = 1/3 orx = -1/21 - 8/21 = -9/21 = -3/7
It is: 2 times the square root of 21 and it's an irrational number
-2
This missing number is 5
21
It is (5+37)/2 = 21.
find the missing number 8-4-9 14-5-2 18-1-? i think it's 2 then the sum of all numbers in each set is 21
The next number in the sequence is 9. The rule is to add 2, then subtract 1, add 2, subtract 1, and so on.
The missing number is 1321!!! Simple Fibonacci row! 0+1=1 1+1=2 1+2=3 2+3=5 3+5=8 5+8=13 8+13=21 13+21=34 ......
8-9-2 = 19 , 12-7-4 = 23. 23 - 19 = 4, therefore we're looking for a third set that is 4 more in sum than the previous set (12-7-4) or 27. 21-4-x = 27, therefore x = 2
6
7*n-n 7*2-2=12 9*2-2=16
16
Find the missing number in the series (in red) :2 , 4 , 5, 9, 9 , 16 , 14 , ? , 20 , ….