It is: 0.37*term+0.5
To find the sum of 25 terms of these arithmetic sequence you can use the formula:Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.Since an = 5t - 3, thena1 = 5(1) - 3 = 5 - 3 = 2a25 = 5(25) - 3 = 125 - 3 = 122By substituting the values we know into the formula we have:S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550Or you can use the formula:Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.In order to find d, we need to find at least the value of 2 terms and subtract them.a1 = 2a2 = 5(2) - 3 = 10 - 3 = 7So d = 7 - 2 = 5By substituting the values we know into the formula we have:S25 = (25/2)[2(2) + (25 - 1)5]S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
Well, isn't that a happy little question! To express 124 as a mixed number, we divide 124 by the whole number part, which is 1, and we get 124 divided by 1 equals 124. So, 124 as a mixed number is 124 over 1. Keep painting those beautiful math problems, my friend!
4
124 inches = 10.333 feet = 3.444 yd 4 yd is bigger
2x2x2x2x2x2x2x2 = 256
4
go ask your teacher and tell him hes dumb
152
215
To find the sum of 25 terms of these arithmetic sequence you can use the formula:Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.Since an = 5t - 3, thena1 = 5(1) - 3 = 5 - 3 = 2a25 = 5(25) - 3 = 125 - 3 = 122By substituting the values we know into the formula we have:S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550Or you can use the formula:Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.In order to find d, we need to find at least the value of 2 terms and subtract them.a1 = 2a2 = 5(2) - 3 = 10 - 3 = 7So d = 7 - 2 = 5By substituting the values we know into the formula we have:S25 = (25/2)[2(2) + (25 - 1)5]S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
Yes.
116
The term common factors specifically refers to the factors shared by two or more numbers. Since 124 is a single number, you could say that it shares all of its factors with itself.The factors of 124 are: 1, 2, 4, 31, 62, and 124.
Pls help
The pattern in the sequence 0, 7, 26, 63, 124 involves the formula ( n^3 - n ), where ( n ) is a positive integer starting from 1. Specifically, for each ( n ): ( 1^3 - 1 = 0 ) ( 2^3 - 2 = 7 ) ( 3^3 - 3 = 26 ) ( 4^3 - 4 = 63 ) ( 5^3 - 5 = 124 ) Thus, the next number in the sequence would be ( 6^3 - 6 = 210 ).
124/124 = 1 124/62 = 2 124/31 = 4 124/4 = 31 124/2 = 62 124/1 = 124
Imagine instead that your equation is (124/10) * (31/10), or, all things being commutative in multiplication, (124 * 31) * (1/10 * 1/10) = (124 * 31) * (1/100) = (124 * 31) / 100. Multiply the first term, and you get 3844. Once you divide from there, you get 38.44.