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well one way to do it is to add:

3 to the first term

5 to the second

7 to the third

9 to the next

we are starting with a1=4, that is the first term and have a sequence where the we add 2n-1 to the n-1 term.

a_n = a_n-1+2n+1 so a_2=4+(2x2-1)=7 a_3=7+(2x3-1)=12 a_4=12+(2x4-1)=19 a_5 is obtained by taking a sub 4, and add (2x5-1) or 19+9=28

a_n means a sub n, where n is the subscript, or course.

So the nth term is a_n=a_n1+(2n-1)...

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wrong, considering:

1st term; 1 + 3 = 4

2nd term; 2 + 5 = 7

3rd term; 3 + 7 = not 12 :')

correctly mentioned though, there ARE other ways of doing this!

take the example of the first term, n=1. square that number, then add 3.

what do you get? 1*1 = 1, 1+3 = 4 (correct)

now try it with others:

2*2 = 4, 4 + 3 = 7

3*3 = 9, 9 + 3 = 12

4*4 = 16, 16 + 3 = 19

5*5 = 25, 25 + 3 = 28

TA-DA! ;D

therefore, the simple answer = n^2+3 (N squared plus three)

- from Adam -

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