well one way to do it is to add:
3 to the first term
5 to the second
7 to the third
9 to the next
we are starting with a1=4, that is the first term and have a sequence where the we add 2n-1 to the n-1 term.
a_n = a_n-1+2n+1 so a_2=4+(2x2-1)=7 a_3=7+(2x3-1)=12 a_4=12+(2x4-1)=19 a_5 is obtained by taking a sub 4, and add (2x5-1) or 19+9=28
a_n means a sub n, where n is the subscript, or course.
So the nth term is a_n=a_n1+(2n-1)...
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wrong, considering:
1st term; 1 + 3 = 4
2nd term; 2 + 5 = 7
3rd term; 3 + 7 = not 12 :')
correctly mentioned though, there ARE other ways of doing this!
take the example of the first term, n=1. square that number, then add 3.
what do you get? 1*1 = 1, 1+3 = 4 (correct)
now try it with others:
2*2 = 4, 4 + 3 = 7
3*3 = 9, 9 + 3 = 12
4*4 = 16, 16 + 3 = 19
5*5 = 25, 25 + 3 = 28
TA-DA! ;D
therefore, the simple answer = n^2+3 (N squared plus three)
- from Adam -
nth term is n squared plus three
28
Oh, what a happy little sequence we have here! To find the pattern, we can see that each term is generated by multiplying the previous term by 2 and then adding 2. So, the nth term can be found using the formula 2^n * 2 - 2. Isn't that just a delightful little formula?
x + (-12) = 28 So x = 28 + 12 = 40
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.The simplest rule for the given sequence of numbers is Un = 5*n + 3.